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Funny Exams and Tests

- He didn't have to add a constant, since it is a de

"He didn't have to add a constant, since it is a defined integral"

 

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What Others Are Saying

 
 
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    • +221
    He didn't have to add a constant, since it is a defined integral
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    • +175
    I wish I understood these comments (:
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    • +38
    You don't need a constant if you're integrating a definite integral. He's integrating a function that's defined from zero to bat, therefore the constant is already defined within bounds of integration.
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    • +38
    lol batman
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    • +32
    question for the people who actually understand that question, is that shit actually usefull to know in your day to day life? i would find batman drawing skills more usefull personally.
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    • +12
    dont click at the link of "very good resourse:" its a virus oder at least NOT A SITE THAT YOU WANT TO OPEN! jesus christ **** this idiots
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    • +9
    The answer is '1'
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    • +8
    yup.
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    • +5
    using the variable you're differentiating with respect to in the boundaries of the integral, -5, assuming man is not a function of bat, integrating bat*man would give you man*((bat^2)/2) which when evaluated between 'bat' and 0 would give you still man*((bat^2)/2. which gives you one half of a bat squared man, not simply a man. differentiating bat*man with respect to bat however would give you just one man which would equate to bruce wayne.
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    • +4
    the integration of brucewayne with d(batsymbol) should give batman and not the other way round. so in any case even his cartoon gets no marks
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    • +3
    lmao integration. Batman to Bruce Wayne xDDDDDD
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    • +3
    Half of these teachers need to go back to English class. Honestly, apostrophes are NOT that hard to use properly.
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    • +3
    d/dbat(Batman)=Wayne
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    • +3
    THIS IS AWESOME!
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    • +2
    O.o AGGH STOOOP WITH THE FREAKY LANGUAGE!!11eleven!!!1!1
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    • +2
    Actually, d/dBatSignal(BruceWayne)=Batman. That's the first fundamental theorem of calculus. Furthermore, Batman =/= Bat Signal. You'll notice, however, that the same logo is on his chest. I'm going to assume that it's something like BatSignal^(1/BatSignal) or something like that. You'd probably have to use L'Hopital's Rule or something anyway.
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    • +1
    Very good. So, spiderman.....
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    • +1
    he didn't have to use calculus to prove batman is bruce wayne, I'm sure simple algebra would have sufficed.
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    OH SHI- I WAS JUST LEARNING INTEGRALS THIS WEEK LAL
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    Whoever think Batman Drawing skills are more important than the question do not know that they would be talking about this in real social gatherings only if many people at Intel did not have these skills.

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