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He didn't have to add a constant, since it is a defined integral
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I wish I understood these comments (:
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You don't need a constant if you're integrating a definite integral. He's integrating a function that's defined from zero to bat, therefore the constant is already defined within bounds of integration.
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lol batman
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question for the people who actually understand that question, is that **** actually usefull to know in your day to day life? i would find batman drawing skills more usefull personally.
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using the variable you're differentiating with respect to in the boundaries of the integral, -5, assuming man is not a function of bat, integrating bat*man would give you man*((bat^2)/2) which when evaluated between 'bat' and 0 would give you still man*((bat^2)/2. which gives you one half of a bat squared man, not simply a man. differentiating bat*man with respect to bat however would give you just one man which would equate to bruce wayne.
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Half of these teachers need to go back to English class. Honestly, apostrophes are NOT that hard to use properly.
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dont click at the link of "very good resourse:"
its a virus oder at least NOT A SITE THAT YOU WANT TO OPEN! jesus christ **** this idiots
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The answer is '1'
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Very good. So, spiderman.....
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THIS IS AWESOME!
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Actually, d/dBatSignal(BruceWayne)=Batman. That's the first fundamental theorem of calculus.
Furthermore, Batman =/= Bat Signal. You'll notice, however, that the same logo is on his chest. I'm going to assume that it's something like BatSignal^(1/BatSignal) or something like that. You'd probably have to use L'Hopital's Rule or something anyway.
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You can't have the variable of integration in the bounds. He should have set up a dummy variable, like (bat-signal)_1 or something like that.
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lmao integration. Batman to Bruce Wayne xDDDDDD
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yup.
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