Howdy Huffers! Check out our newest photo site Ad Failure!
We’ve also launched some text based sites you may enjoy: Anti Joke, Anti Pickup Line, Pointless Superpowers, and Clarksonisms.
Howdy Huffers! Check out our newest photo site Ad Failure!
We’ve also launched some text based sites you may enjoy: Anti Joke, Anti Pickup Line, Pointless Superpowers, and Clarksonisms.
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Dambo? Is it really you?
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If I had points to spare, I would totally do this
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i found x! "... x"
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gringos maricas por eso es q la gente mas estúpida e ignorante vive allá lástima jajaja llorenla perros hijueputas!!! jajajaja
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:)))))))))))))))))))))))))))))) i can't stop laughing xD "No. there's an elephant in the way."
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That question is scientifically flawed. The elephant IS in the way. Kudos to the kid!
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Elaphant=FTW
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Oh god, I literally LOL'd.
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At all the retards commenting on the frictionless ramp. Unless you're trolling (in which case you aren't a retard), this is theoretical physics. Anyone with half a brain knows that a frictionless ramp doesn't exist.
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IRRELEPHANT!
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looks like the elephant is gonna get smashed by the 3kg-object.. ;D
poor elephant.. RIP! :'(
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someone get that elephant out of v way
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Crap. Too much time in physics. Figured it out in my head. Crap. BTW, x=5.4m.
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it means move back, up the slope.. it has to do with the spring constant
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I LOVE THIS ANSWER XD!
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in response to this ===> "(b) Does the object continue to move after it comes to rest?" - ummmm no.
I must say, who ever said that is totally retarded. the oject wil rest for a small glimps of time then be shot back up the ramp by the spring...... dear God who ever said that is dumb
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That was a stupid answer. The kid was doing everything just right.
Ug = mgh = (3.00kg)(9.81m/s^2)(5m) = 147J
Us = .5kx^2 = .5(100N/m)x^2
By the Work-Energy Theorem:
Ei = Ef
Ug = Us
mgh = .5kx^2
x = sqrt(2mgh/k)
x = sqrt[2(3.00kg)(9.81m/s^2)(5m)/(100N/m)]
x = sqrt(2.943m^2)
x = 1.72m
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Holy shit. I know this kid :D I was in his class. I lol'd so hard when I saw his test back.
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look out elephant!...its coming to spank you!!
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That problem is so easy. All you have to do is set 1/2kx^2 equal to mgh and solve for x.
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